log(base 4)3 + log(base 4)8 - log(base 4)6
= log(base 4) (3 x 8 / 6)
= log(base 4)4
= 1.
2007-04-28 10:26:19
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answer #1
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answered by Anonymous
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since all bases are the sameyou can comine the #'s
log(base 4)(3*8/6)
log(base 4)4
what power can you put on 4 to get 4? 1
2007-04-28 17:40:29
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answer #2
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answered by Matia 3
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Remember that
log(base a) of b =log(b)/log(a) so
(log(3) + log(8) - log(6))/log(4) = 1
HTH
Doug
2007-04-28 17:30:53
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answer #3
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answered by doug_donaghue 7
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You have to use the difference of to logs. for the last part.
you know M-N = M/N
it would be log *4* 8/6
2007-04-28 17:27:07
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answer #4
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answered by lithiumjuice 2
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log(base4)[3*8/6] = log(base4)[4] = 1
2007-04-28 17:45:35
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answer #5
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answered by John 2
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well i dont really understand what the question is asking but mayb you have to multiply the first 2 numbers then add the product of the next two numbers then substract the product of the last 2 numbers.
2007-04-28 17:25:31
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answer #6
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answered by itsgoingtobealright 3
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Get out your text book........now your notes.........now grab a pencil.............turn on the desk lamp........now.........
DO YOUR OWN F^CKING HOMEWORK!
2007-04-30 13:48:22
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answer #7
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answered by Anonymous
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