How many grams of hydrochloric acid are reacted when 1.20 mol of zinc is reacted with 7.80 mol of hydrochloric acid, as shown above?
i tried a bunch of things..but doesn't seem to be correct. Need help!!
2007-04-28 09:59:16 · 3 answers · asked by wonderer 1 in Science & Mathematics ➔ Chemistry
1.20molZn x 2molHCl/1molZn x 36.5gHCl/1molHCl = (1.20)(2)(36.5) = 87.6g HCl
2007-04-28 10:10:28 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
this is just a mass-to-liters type of problem. first, convert the 3.27g Zn into moles: ** 3.27 g / 65.4 (g/mole) = 0.05 moles of Zn next, use the balanced equation to see how many moles of H2 gas can be formed (since extra HCl is used, you dont need to worry about that): ** the Zn:H2 ratio is 1:1 -- so however many moles of of Zn you start with, thats how many moles of H2 is formed. ** so, the amount of moles of H2 formed is 0.05 moles then, just convert this amount to liters: ** 0.05 moles x 24.5 (L/mole) = 1.225 L and there ya go
2016-05-21 00:47:28 · answer #2 · answered by ? 3 · 0⤊ 0⤋
1.2 x 2 x 36.5 grams
2007-04-28 10:04:32 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋