Algebra and Trig question. Please show work! Serious replies only!! I really do appreciate the help?

Question

Find the exact values ( in lowest terms) of sec A and csc A using the right triangle in the box and the information x=75 y =40, z =85

* Since I cant draw the triangle, I will explain it. AB is z....BC is x....CA is y


a). sec A = 17/15; csc A = 17/8
b). sec A = 8/17; csc A = 15/17
c). sec A = 15/18; csc A =8/15
d). sec A = 17/8; csc A= 17/15

Answer 1

By definition: sin A = 75/85 and cos A = 40/85
Then: sec A = 1/cos A = 85/40 = 17/8 and
csc A = 1/sin A = 85/75 = 17/15

So it looks like (d) is the answer.

Answer 2

d. This is an 8/15/17 triangle in disguise. Angle A is the larger of the two non-right angles. The csc is reciprocal sin (which is 15/17) and the sec is reciprocal cosine (which is 8/17).

Answer 3

Recall sec is the reciprocal (or multiplicative inverse) of cos, and csc is the reciprocal of sin.

sin -> opposite / hypotenuse; csc -> hypotenuse/opposite
cos -> adjacent / hypotenuse; sec -> hypotenuse/adjacent

The hypotenuse is the longest side in a right triangle (or the side opposite of the right angle), so it is side z: length 85.

A touches side y and z. B touches side x and z. C touches side x and y.

sec A is therefore: z / y = 85/40 = 17/8
csc A is therefore: z / x = 85/75 = 17/15

Your answer is D.

Answer 4

The triangle you have 40 75 85 is the equivalent of an 8 15 17 right angle triangle (divide by 5)

Sec(x) and Cosec(x) must be greater than 1
Sec(x) = 1/cos(x) and I think that cos(x) = 8/17 (Adjacent over hypotenuse)
So the answer must be d)

Answer 5

i may not be a math whiz. but i'm not sure what you're looking for. i know you can get the secant values by doing cosine and flipping it. where did you get the 17/15 and other values? are those your answers?

if those weren't there. you can find the secant of A by drawing it out and getting cosA=40/85 and then flipping it to get secA=85/40 reducing to 17/8

for cscA...you find sinA and then flip it..sinA=75/85 so cscA=85/75 and reduce to 17/15

so looks like it's D.)


i'm not a hundred percent sure..i haven't done trig in awhile.

and etc. for the rest of the problems...just use SOH-CAH-TOA

Sin is Opposite over Hypotenuse
Cosine is Adjacent over Hypotenuse
Tangent is Opposite over Adjacent

Answer 6

I don't think this makes sense

d