linear momentum?

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In 9.99 s, 217 bullets strike and embed themselves in a wall. The bullets strike the wall perpendicularly. Each bullet has a mass of 5 x 10-3 kg and a speed of 1170 m/s. (a) What is the average change in momentum per second for the bullets?

2007-04-28 09:21:10 · 2 answers · asked by Hilary R 1 in Science & Mathematics ➔ Physics

2 answers

The -total- change in momentum is
Mt = 217*5x10^(-3)*1170 = 1269.45kg-m/s and the average per second is
1269.45/9.99 = 127.07 kg-m/s

HTH

Doug

2007-04-28 09:30:08 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋

[(217) * 5 *10^-3 * 1170 ]/9.99
(No of bullets * Mass * Velocity) / time taken for them to hit wall)

2007-04-28 16:27:01 · answer #2 · answered by welcome news 6 · 0⤊ 0⤋