It's a math problem and I can't seem to figure it out.
2007-04-28 09:02:17 · 10 answers · asked by mari 1 in Science & Mathematics ➔ Mathematics
2(x + 2)^2
2(x + 2)(x + 2)
2(x^2 +2x + 2x + 4)
2(x^2 + 4x + 4)
2x^2 + 8x + 8
2007-04-28 09:05:45 · answer #1 · answered by skm4usa 3 · 0⤊ 0⤋
It depends on what your teacher is asking. You can foil it out and simplify like MikeX did, and get a quadratic equation, or you can actually solve for x, (assuming the whole equation equals 0) in which case you don't want to simplify. Start by expanding the equation to
2(x+2)(x+2) then break off (x+2) and solve for x.
x+2=0 then x=-2 Because both factors are (x+2) you only need to do it once, and you'll only have one value for x.
2007-04-28 09:29:56 · answer #2 · answered by Anonymous · 0⤊ 0⤋
=2(x^2+4x+4)
=2x^2+8x+8
2007-04-28 09:05:23 · answer #3 · answered by Lu Lu 2 · 0⤊ 0⤋
2(x+2)^2
2007-04-28 09:05:00
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answer #4
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answered by DiMooch 3
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=2(x+2)(x+2)
=2(x^2+2x+2x+4)
=2(x^2+4x+4)
2(x+2)^2
2(x^2+4x+4)
2x^2+8x+8
2007-04-28 09:07:45 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
2(x+2)(x+2)
2(x^2+4x+4)
2x^2+8x+8
2007-04-28 09:21:09 · answer #6 · answered by :) 5 · 0⤊ 0⤋
Let me give it a try:
2(x^2+4x+4)=2x^2+8x+8
As a side note:
x^2-y^2=(x-y)(x+y)
(x-y)^2=x^2-2*xy+y^2
(x+y+z)^2=x^2+y^2+z^2+2(xy+yz+xz)
2007-04-28 09:07:35 · answer #7 · answered by Anonymous · 0⤊ 0⤋
you cant figure it out because you dont know what X is
2007-04-28 09:05:03 · answer #8 · answered by Christine 3 · 0⤊ 0⤋
I assume ur simplifiing so here it goes..
2(x+2)^2
2(x+2)(x+2)
i cant do much else unless ur tell us wat ur tryin to do
srry
:)
2007-04-28 09:52:07 · answer #9 · answered by bt 1 · 0⤊ 0⤋
What does it equal?
2007-04-28 09:04:37 · answer #10 · answered by Chidinma 3 · 0⤊ 0⤋