Let S be the cylinder x^2 + y^2 = 1, 0 <= z <= 6. Find {double integral of S}(x^4 + (2x^2)(y^2) + y^4)^2 dS.

Question

This is all that is given.

I believe I'm supposed to parametrize, but I'm not sure...?? If so, I still do not know how

Answer 1

Exactly what do you want? The cylinder equation does not lead to[ (x2+y2)^2]^2. Rather, you solve the cylinder for y in terms of x, y= +/-sqrt(1-x^2) and integrate ydx with these limits, followed by integration by z from 0 to 6

Answer 2

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Answer 3

what the heck