A chemists determines that a sample of petrified wood is 4.50 X 103 years old. What is the rate of decay,?

Question

in counts per minute per gram, of carbon-14 in the sample?

The decay rate of carbon-14 in wood today is 13.6 counts per minute per gram, and the half life of carbon-14 is 5730 years.

For a first order reaction the rate R = −k N so the ratio of rates at two different times is given by R(t1)/R(t2) = N(t1)/N(t2).
For nuclear decay the rate is ofen is expressed in units of counts per unit of time.

Answer 1

(1) recheck your problem statement. It seem like you already answered your question.

Answer 2

Ok so, if anyone hasn't done this in time for you to answer I'm sorry, these people are retarded, but to be fair all you had to do was open a book.

ln (Nt / No) = -kt

k = .693 / t 1/2

so, .693 / 5760 = whatever, put it in your calc

e^(-ans(time they tell you)) = Nt / No

No * this = Nt

Ans = 7.891837