balanced equation: Al(OH)3 + 3 HCl -> AlCl3 + 3 H2O
2007-04-28 07:46:01 · 4 answers · asked by soccrrulz21 2 in Science & Mathematics ➔ Chemistry
Convert mass of Al(OH)3 into moles using its molar mass.
Multiply moles of Al(OH)3 X 3 since the balanced equation shows that 3 moles of HCl react with 1 moles of Al(OH)3
Divide the moles of HCl by 0.430 to give you Liters of HCl.
2007-04-28 07:51:07 · answer #1 · answered by hcbiochem 7 · 1⤊ 0⤋
112 mL of 0.430 M HCl
2007-04-28 09:08:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋
112 mL of .430 M HCl is needed.
2007-04-28 07:56:37 · answer #3 · answered by charlesc121227 1 · 0⤊ 1⤋
use the molecular mass of calcium hydroxide to alter g to moles of Ca(OH)2. because of the fact that there are 2 moles of OH according to mole of molecules the variety of moles of OH- to be neutralized is double the moles of Ca(OH)2. this could be equivalent to the variety of moles of H+ mandatory to neutralize the backside (it takes one H+ to neutralize one OH-) because of the fact that there is in simple terms one H+ interior the acid this can be equivalent to the variety of moles of HCl mandatory. Use the Molarity formula (M = moles/liters) to sparkling up for liters.
2016-12-28 03:46:48 · answer #4 · answered by luques 3 · 0⤊ 0⤋