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For a first order reaction the rate R = −k N so the ratio of rates at two different times is given by R(t1)/R(t2) = N(t1)/N(t2).
For nuclear decay the rate is ofen is expressed in units of counts per unit of time.


A chemists determines that a sample of petrified wood is 3.50 X 103 years old. What is the rate of decay, in counts per minute per gram, of carbon-14 in the sample? The decay rate of carbon-14 in wood today is 13.6 counts per minute per gram, and the half life of carbon-14 is 5730 years.

2007-04-28 07:44:44 · 1 answers · asked by guitarx313 1 in Science & Mathematics Chemistry

1 answers

R/13.6 = 3500/5730

Solve for R.

2007-04-29 05:52:04 · answer #1 · answered by Gervald F 7 · 0 0

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