will the time of ascent be equal to the time of descent..wen we throw an object vertically up.air resist const

Question

when we throw an object vertically up , will the time of ascent be equal to the time of descent... doesnt that depend upon the force by which we r throwing

Answer 1

Yes they will be equal in case of no air resistance.
But if air resistance is considered then
T ascent due to viscous drag due to air.
But the difference is almost negligible.

Answer 2

THey WILL be equal--always. Regardless of the force you use, gravity slows the ascent at a constant rate, and then accelerates the object on the descent by the same amount.

So, the trip up and the trip down will be equal in time. Also, the velocity of the object at the bottom of the descent will exactly equal its initial velocity.

Answer 3

The "throw" is an impulse and it gives the object its initial speed needed to go up. After that gravity takes over.

In the absense of friction, the trip up and down is equal due to symmetry.

Friction is another story. If friction is just air, there is no noticeable difference. Now imagine the whole situation inside a bottle of very thick oil. You will find that the object being shot up with, say high speed, will eventually come to a stop and then it will slowly come up under gravity. Viscousity of the resistive medium comes into play.

Answer 4

The time of ascent will be equal to time of descent if the initial velocity (u) with which the object is vertically thrown up is equal to final velocity(v) of the object in its descent

Answer 5

While I seem to be out numbered at the moment, they will be equal, the force that stops the object on the way up, is the same force that brings it back down (gravity).

Answer 6

Yes time of ascent is equals to the time of descent.
If we through any object with more greater force it will take more time to obtain highest peak & as for giving greater force peak will so high.&to come it will take a large interval.
but the asending will remains equal to disending time.

Answer 7

The times will be equal if air resistance is ignored.
The kinematics equation for this is:
vf = v0 + at
in this case, a = g, gravitational acceleration.
vf is final speed, v0 is initial speed. On the way up, vf is zero, and on the way down, v0 is zero. so..
on the way up:
v = -gt
t = v/g (time can't be negative)
on the way down:
v = gt
t = v/g

As you can see, the two times are the same.

Answer 8

yes the time of ascent and descent are the same, it doesnt sepend on the speed thrown.

Answer 9

Almost never will they be equal. YOU control the ascent, but GRAVITY defines the descent.

Answer 10

If air resistance is to be considered, no. In a vacuum, yes.