Given the unbalanced equation: NaNo3-------NaNo2 + O2
2007-04-28 05:47:51 · 3 answers · asked by jere 1 in Science & Mathematics ➔ Chemistry
I'll give you the steps you should take and you should be able to do the rest.
1. Balance the equation
2. Using n = PV/RT, figure out how many moles of O2 occupy 2.55L of volume
3. Use n(moles O2) above to figure out how many moles of sodium nitrate you must start out with using stoichiometry
4. Convert moles sodium nitrate to grams using molar mass
I'm pretty sure that's right.
2007-04-28 06:03:17 · answer #1 · answered by mandrake 2 · 0⤊ 0⤋
mandrake is right, but is complicated.
Since the conditions are at STP, the ideal gas law is not necessary. Just stoichiometry is sufficient.
1. Balance the equation
2. Convert 2.55 L of O2 to moles by dividing by 22.4 L /mole
3. Multiply by the appropriate molar ratio to get moles of NaNO3.
4. Multiply by the molecular mass of NaNO3 to get grams.
2007-04-28 06:20:46 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋
2.5L divided through 22.4 L/mol you receives the quantity of mols of oxygen gasoline. From there multiply the quantity of mol of oxygen gasoline with the Relative Molecular Mass of Oxygen (32g/mol) you should get the answer to be 3.571 grams
2016-11-23 12:48:56 · answer #3 · answered by ? 4 · 0⤊ 0⤋