A 2.00 L bottle contains N2 gas at pressure of 4.80 atm.?

Question

What is the mass of the gas if the temperature is 100.0 degrees celsius?

Answer 1

T = 100.0 + 273 = 373 K

from the equation

pV = nRT

n = pV /RT = 4.80 x 2.00 / 0.0821 x 373 = 0.313 mole N2

One mole of N2 weights 28 g

1 : 28 = 0.313 : x

Mass N2 = 8.78 g

Answer 2

PV = nRT = gRT/MM
g = PV*MM / RT = 4.80 atm * 2.00 L * 28.0 g/mol / (0.08206 * 373 K)
g = 8.78 g

Answer 3

PV = nRT = gRT/MM
g = PV*MM / RT = (4.80 atm)(2.00 L)(28.0 g/mol) / (0.08206 * 373 K)
g = 8.78 g