8x^3=-1
8x^3+1=0
(2x+1)(4x^2-2x+1)=0
x= -1/2
Or
8x^3=-1
x^3= -1/8
x= -1/2
2007-04-28 03:44:18
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answer #1
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answered by Anonymous
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Solve 8x^3=-1
2 -step solution !
1) So x^3=-1/8 or x^3= -1/(2^3)
2) Taking the cube root for both sides of the equation,
x= -1/2
(The cube root of 1= 1 and the cube root of -1 = -1, since -1 X -1 X -1 = -1 )
2007-04-28 04:08:13
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answer #2
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answered by jimmy 7
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a million) 8x^3 = -27 x^3 = -27/8 x = - 3/2 answer 2) x^4 - 8x^2 +15 x^4 -3x^2 -5x^2 +15 x^2 ( x2 -3) -5 (x^2 -3) ( x^2-5) ( x^2-3) answer 3) 4x^2 = 36 x^2 = 9 x = +3 OR -3 answer
2016-12-10 13:42:41
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answer #3
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answered by ? 4
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Step 1. divide bothe sides of the equation by 8. You will get x^3=-1/8.
Step 2. Since x is cubed, take the cubed root of both sides. Start with the left side being x and on the right side you have the negative (cubed root of one divided by the cubed root of eight). Since the cubed root of 1 is 1, and the cubed root of 8 is 2, You should get
X=-1/2.
Step 3. Check your answer and put -1/2 back into the original equation for X and see if the left side of the equation = the right side. 8(-1/2)^3=-1 and then, 8(-1/8)=-1. -1=-1!!!!!!!
Therefore X=-1/2!!!!!!!!!!!
2007-04-28 04:08:30
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answer #4
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answered by ? 1
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-1/2
2007-04-28 03:40:41
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answer #5
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answered by Anonymous
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8x^3 = - 1
x^3 = -1/8
x = i/2
2007-04-28 03:41:15
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answer #6
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answered by calvin o 5
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X^3 =-1/8
And -1/8 is the power 3 of -1/2
so answer -1/2
2007-04-28 03:40:11
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answer #7
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answered by maussy 7
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Here too there are 3 roots, one real and two complex.
x = -(1/2) is the real one and -(1/2)w & -(1/2)w^2 are the complex roots where w is the complex cube root of unity.
2007-04-28 03:44:36
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answer #8
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answered by nayanmange 4
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8x^3=-1
x^3=-1/8
x=-+1/2
2007-04-28 03:35:00
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answer #9
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answered by Anonymous
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-1/2
x can not be +1/2, because 8(1/2)^3=1, not -1...
2007-04-28 03:34:23
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answer #10
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answered by Mixed Asian 5
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