English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Assume there is a strange tiny planet. Its gravitational acceleration at its surface is exactly 10.0 metres per second per second, and its diameter is exactly 2100 kilometres.

Also, a completely unrelated fact, the "Aliens" are able to consume about 0.4 kg of pretty much anything they want to eat, every minute, nonstop.

Assuming that the density of the planet is uniform, and that orbiting bodies don't significantly affect the planet's gravity, how many years will it take one million "Aliens" to consume one cubic kilometre of the tiny planet?

2007-04-28 02:24:21 · 3 answers · asked by Nick 3 in Science & Mathematics Physics

3 answers

So one million "Aliens" are able to consume 2.6kg an hour of anything. So lets say 1 metre squared is 1kg of anything. If the aliens are eating... 2.6 metre squared every hour, then after an Earth day they will have eaten 62.4 metre squared. Then roughly 16 days they will have eaten 1,000 metre (or 1km) squared of material. 33654 (rounded) days they will have eaten there entire planet.

2007-04-28 02:40:28 · answer #1 · answered by Anonymous · 0 0

F=m1a
For gravity it is Fg=(m1Xm2)X gravitational constant (g)/r^2

m2=mass of planet m1=mass of falling object

m1a=(m1Xm2)X gravitational constant (g)/r^2

a=m2Xg/r^2

10 = m2 Xg/r^2

r= 1050 kilometers

Look up the gravitational constant in a book under newtons formula for gravity.

When you have the mass, divide by 400,000 kg of mass per second. Then convert to years.

2007-04-28 02:47:51 · answer #2 · answered by eric l 6 · 0 0

Let the aliens consume each other instead of the planet.

2007-04-28 02:48:38 · answer #3 · answered by Swamy 7 · 0 0

fedest.com, questions and answers