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drawing a graph of Phase difference of (Pi/4). can I just add to any point on the wave 45 degrees.

But if I will plot a displacement - Time graph, I have to find the corresponding T using the formula (Phase difference = (delta t / T) * 2pi) correct?

2007-04-27 21:49:35 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

You are about right.
If you need to draw:

sin(w*t + pi/4)............(1),

where pi/4 is phase difference (in comparison to sin(w*t)), w = 2*pi*f, f = 1/T, and T is a period. Then you can write (1) as:

sin(w*(t + (pi/4)/w) = sin(w*(t + (pi/4)/(2*pi*f)) = sin(w*(t + T/8))

which is the sin(w*t) shifted in time to the left by T/8 (the eight-th of a period, as the pi/4 is the eight-th of 2*pi).

2007-04-28 01:34:43 · answer #1 · answered by fernando_007 6 · 0 0

You must shift it accordingly.

2007-04-28 05:10:00 · answer #2 · answered by ag_iitkgp 7 · 0 0

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