This is just giving me a headache...
solve the system:
2x + y - z = 3
x + 4y + 3z = 5
2x - 5y + 4z = -3
2007-04-27 20:09:40 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x + y - z = 3 equation(1)
x + 4y + 3z = 5 equation(2)
2x - 5y + 4z = -3 equation(3)
Subtract equation(1) from equation(3)
6y - 6z = 6
:. y = z + 1 equation(4)
Replace equation (4) into equation(2)
x + 4(z + 1) + 3z = 5
x + 7z = 1
Put z = 1
y = 2 and x = -6
2007-04-27 20:25:30 · answer #1 · answered by Tubby 5 · 0⤊ 0⤋
2x + y - z = 3 equation(1)
x + 4y + 3z = 5 equation(2)
2x - 5y + 4z = -3 equation(3)
Subtract equation(1) from equation(3)
6y - 6z = 6
:. y = z + 1 equation(4)
Replace equation (4) into equation(2)
x + 4(z + 1) + 3z = 5
x + 7z = 1
Put z = 1
y = 2 and x = -6
2007-04-28 06:12:54 · answer #2 · answered by chndr_vny 1 · 0⤊ 1⤋
6x + 3y - 3z = 9
x + 4y + 3z = 5----ADD
7x + 7y = 14
8x + 4y - 4z = 12
2x - 5y + 4z = - 3---ADD
10x - y = 9
7x + 7y = 14
10x - y = 9
7x + 7y = 14
70x - 7y = 63---ADD
77x = 77
x = 1
7 + 7y = 14
y = 1
x + 4y + 3z = 5
1 + 4 + 3z = 5
z = 0
x = 1, y = 1, z = 0
2007-04-28 03:39:59 · answer #3 · answered by Como 7 · 0⤊ 0⤋
1=4/3z
2014-02-06 17:48:30 · answer #4 · answered by J. 1 · 0⤊ 0⤋
X=-9 ; Y=11 ; Z=-10 use matrix algebra to solve
2007-04-28 03:45:42 · answer #5 · answered by lahomaokie 2 · 0⤊ 0⤋
I think someone is trying to teach you Gaussian elimination.
1..4..3..5
2..1..-1..3
2..-5..4..-3
1...4...3...5
0...-7..-7..-7
0..-13..-2..-13
1...4...3....5
0...1....1....1
0..-13..-2..-13
1..0..-1..1
0..1...1..1
0..0..11..0
1..0..-1..1
0..1...1..1
0..0...1..0
1..0..0..1
0..1..0..1
0..0..1..0
so we have x=1, y=1 and z=0
2007-04-28 03:25:46 · answer #6 · answered by Roy E 4 · 0⤊ 1⤋
x = 1
y = 1
z = 0
HTH
Doug
2007-04-28 03:24:25 · answer #7 · answered by doug_donaghue 7 · 0⤊ 1⤋