2x^2+ 5x + 3 = 0. Find x. When you figure this, what steps do you take?

Answer 1

This can be solved easily by factorisation
2x^2 + 5x + 3 = 0
2x^2 + 2x + 3x + 3 = 0
2x(x + 1) + 3(x + 1) = 0
(2x + 3)(x + 1) = 0

Either x + 1 = 0 (or) 2x + 3 = 0
x = -1 (or) x = -3/2

x = -3/2, -1 are the roots of this equation.

Answer 2

Just factorize the equation:

2x^2 + 5x + 3 = 0

so ( 2 x + 3) * (x + 1) = 0

then there'll only be 2 possibilities
2x + 3 = 0, x = -3/2
or
x + 1 = 0, x = -1

Answer 3

Kuan T started well, but got confused.
Reversing FOIL,
2*1 = 2 (F)
2*1 + 1*3 = 5 (O & I)
1*3 = 3 (L)
so
(2x + 3)(x + 1) = 0
If 2x + 3 = 0 the equation holds, and if x + 1 = 0 the equation holds. Solving the two equations you get
x = -3/2 or -1

When no integers work for reversing FOIL, you must use other methods.

Answer 4

x= -1, -3/2

Answer 5

2x^2+2x+3x+3=0
(2x+3)(x+1)=0
2x+3=0 or x=-3/2
x+1=0 or x=-1

Answer 6

2x^2+ 5x + 3 = 0
Find factors of the constant (3)
1, 3
Now, how do you get 5 using, 1, 2 and 3
2*1+3=5
(2x +3)
(x+5)
(2x +3)(x+5) =0
so, either
x+5 =0 or 2x+3 = 0
x =-5 or 2x =-3
x =-3/2
= -1/1/2 or -1.5

Answer 7

2x^2+5x+3=0
2x^2+2x+3x+3=0
2x(x+1)+3(x+1)=0
(2x+3)(x+1)=0
x={-3/2, -1}

Answer 8

(2x + 3).(x + 1) = 0
Either first or second bracket must equal zero:-
x = - 3 / 2
x = - 1