My answer was originally 15,1 but it turned out to be wrong.
2007-04-27 19:33:21 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2-14x-15=0
(x-15)(x+1)=0
2007-04-27 19:36:01 · answer #1 · answered by Anonymous · 0⤊ 1⤋
x² - 14x - 15 = 0
(x - 15).(x + 1) = 0
x = 15, x = - 1
2007-04-27 20:55:34 · answer #2 · answered by Como 7 · 0⤊ 0⤋
x^2- 14x = 15
x^2- 14x -15 = 0
(x-15)(x+1)=0
x=15 or -1
2007-04-27 20:06:58 · answer #3 · answered by Tubby 5 · 0⤊ 0⤋
1) in x^2-14x-15=0 Look at the integer without coefficient , -15,
2) -15 is made of a -1*15 or a 1*-15
3) look at the integer with x coefficient (-14)
4) -14 is made of -15+1
to get the result look at steps 2 and 4 ---->-15 &1 are factors
------> (x-15)*(x+1)=0
------>x-15=0 => x=15
------>x+1=0 => x=-1
the general rule is:
if equation is like : x^2+(a+b)*x+(a*b)=0
factors are: (x+a)*(x+b)=0 ==> x=-a, x=-b
2007-04-27 19:53:11 · answer #4 · answered by little elephant 1 · 0⤊ 1⤋
x^2 -14x =15
x^2 - 14x -15 = 0
(x-15) (x+1) = 0
x=15 or x=-1
2007-04-27 22:28:31 · answer #5 · answered by Bharat 4 · 0⤊ 1⤋
x^2-14x=15
x^2-14x-15=0
x^2-15x+x-15=0
x(x-15)+1(x-15)=0
(x+1)(x-15)=0
x=15 or -1
So you are partially right.
2007-04-27 20:15:48 · answer #6 · answered by Harsh 2 · 0⤊ 0⤋
so,
x=15 and
x=-1
2007-04-27 19:38:24 · answer #7 · answered by hpage 3 · 0⤊ 1⤋
(x-15)(x+1)=0
x=15 or -1
2007-04-27 19:37:04 · answer #8 · answered by raj 7 · 0⤊ 1⤋
ANS: (15,-1)
2007-04-27 20:55:14 · answer #9 · answered by Sharon 2 · 0⤊ 0⤋