2007-04-27 19:31:52 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2-7x+10=0
x^2-5x-2x+10=0
x(x-5)-2(x-5)=0
(x-2)(x-5)=0
x=2 or 5
2007-04-27 20:19:24 · answer #1 · answered by Harsh 2 · 1⤊ 0⤋
x^2 - 7x = -10
x^2 - 7x +10 = 0
(x - 5)(x - 2) = 0
x = 5, x = 2
2007-04-27 19:34:50 · answer #2 · answered by Anonymous · 1⤊ 1⤋
x^2 - 7x + 10 = 0
(x - 5)*(x - 2) = 0
x = 5 or x = 2
2007-04-27 19:34:23 · answer #3 · answered by ........ 5 · 1⤊ 1⤋
x² - 7x + 10 = 0
(x - 5).(x - 2) = 0
x = 5, x = 2
2007-04-27 20:56:53 · answer #4 · answered by Como 7 · 1⤊ 1⤋
x^2- 7x = -10
x^2-7x+10=0
(x-5)
(x-2)
(x-5)(x-2) =0
(x-2) =0
x = 2
or
(x-5)==0
x=5
2007-04-27 19:42:31 · answer #5 · answered by Kuan T 2 · 1⤊ 1⤋
1) in x^2-7x+10=0 Look at the integer without coefficient , 10,
2) 10 is made of a 2*5
3) look at the integer with x coefficient (-7)
4) -7 is made of -2+(-5)
------> (x-2)*(x-5)
the general rule is:
if equation is like : x^2+(a+b)*x+(a*b)=0
factors are: (x+a)*(x+b)=0
2007-04-27 19:43:59 · answer #6 · answered by little elephant 1 · 1⤊ 1⤋
x^2-7x+10=0
(x-5)(x-2)=0
2007-04-27 19:34:49 · answer #7 · answered by menkhepyra 2 · 1⤊ 1⤋
x2-7x+10
(x-2)(x-5)
x=5,2
2007-04-27 19:34:27 · answer #8 · answered by Anonymous · 1⤊ 1⤋
Well ... every 1 got teh right answer here :) why should i bother ... GOod luck on ur H.W/exam.....
2007-04-27 19:36:37 · answer #9 · answered by Anonymous · 1⤊ 1⤋