I thought my answer was right. I'm a little confused as to how to get the slopes. Is it (m = -2, b = -2)...(m = 0, b = -2)...(m = -2, b = 0)...(m = 2, b = 0) ?
2007-04-27 17:38:38 · 11 answers · asked by Scott H 1 in Science & Mathematics ➔ Mathematics
The basic equation is y = mx + c, where m is the gradient and c is the y-intercept.
Since the equation is y = -2x,
m = -2 and b = 0.
2007-04-27 17:43:03 · answer #1 · answered by glade_moonstone 3 · 0⤊ 0⤋
since the equation for a straight line is"
y = mx + b
where m = slope and b = y intercept
m = -2 and b =0
Quick checking:
Assume x = 3
y = -2 (3)
y = -6
so (3, -6) falls on the line
since we know b = 0, we know that for the place where the line intercepts the y-axis is 0
so when x = 0
y = -2(0)
y = 0
so (0, 0) also falls on the line
the slope is the inclination of the line. It means that for every unit in y, x decreases twice (it would increase if the slope was a positive number)
the formula to find the slope of a line when you know two points on the line is:
m = (y2 - y1) / (x2 - x1)
If we input our coordinates in that formula
m = (0 - (-6)) / (0 - (3))
m = -6 / 3
m = -2
2007-04-28 01:02:39 · answer #2 · answered by Weakest 2 · 0⤊ 0⤋
Remember that the formula for a straight line is y=mx+b. The number x is multiplied by is m, the slope. Therefore m in this problem is -2. There is nothing added to the x term in this equation, so b=0. The equation actually looks like this:
y=-2x+0
2007-04-28 00:42:55 · answer #3 · answered by Pius Thicknesse 4 · 0⤊ 0⤋
OK, the generic equation is y=mx+b
The slope is always m, so -2 would be the slope.
Once you know the slope you can solve algebraically to get the y-intercept. You would add a y coordinate into the y variable and an x coordinate into the x variable. So, it'd be y=-2x+b. In this case the y-intercept would be 0.
2007-04-28 00:51:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋
The slope (m) is the X coefficient, so -2.
The y-intercept (b) is the constant added to it - in his case, 0.
y=mx+b
y=(-2)x+(0)
y=-2x
2007-04-28 00:42:56 · answer #5 · answered by someone 3 · 0⤊ 0⤋
If you an equation in the form
y = mx + b where m is the coefficient of x and b is constant
m is the slope of the line.
b is the y - intercept
In your equation
y = -2x,
the slope m = -2 , b = 0
2007-04-28 07:41:31 · answer #6 · answered by detektibgapo 5 · 0⤊ 0⤋
y = -2x
the coefficient of x is the slope
m=-2
for x=0 then b=-2*0=0
answer: m = -2, b = 0
2007-04-28 00:48:05 · answer #7 · answered by iyiogrenci 6 · 0⤊ 0⤋
y=mx+b
m =-2
b=0
y=-2x is same as y=-2x+0
2007-04-28 01:04:53 · answer #8 · answered by Malu23 1 · 0⤊ 0⤋
for
y = mx + b
then
y = -2x
m = -2
b = 0
where m is slope
which = the first derivative of the function given
I hope this helps
2007-04-28 00:43:20 · answer #9 · answered by M. Abuhelwa 5 · 0⤊ 0⤋
y=mx
b=mb X x mb=m x ---:y=-2x
m=-2 b=-2
m=0 b=-2
m=-2,b=-0
m=2 b=-1
2007-04-28 00:50:58 · answer #10 · answered by Faisal R 3 · 0⤊ 0⤋