the two 5's are saparated right?
x^2/5 + 5 = 0
subtract 5 for both sides
x^2/5 = -5
mulitply 5 for both sides
x^2 = -25
take a square root
x = sqrt(-25)
since you can't have a negative number under square root, there is no solution. However, if you want to use complex number, then x = +/-5i
2007-04-27 16:47:23
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answer #1
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answered by 7
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x^2 divided by 5 + 5=0
x^2 divided by 5 = -5
x^2 = -25
x = sqrt(-25)
x = +- 5i
2007-04-27 23:48:57
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answer #2
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answered by cat n 3
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x^2/5 + 5 = 0
5(x^2/5) + 5(5) = 5(0)
x^2 + 25 = 0
x^2 = -25
no answer~
2007-04-27 23:46:43
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answer #3
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answered by octo 1
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x^2 divided by 5 + 5= 0
therefore x^2= negative 5
therefore 2 log x = negative 5
lol questions screwed theres no possible answer, for both unless you use comples number suggested by guy above,
2007-04-27 23:52:10
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answer #4
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answered by Anonymous
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x^2/5 +5=0
x^2/5+5-5=0-5
x^2/5=-5
x^2=-25
x=+/- 5i
2007-04-28 02:10:55
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answer #5
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answered by Dave aka Spider Monkey 7
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