Algebra 2 question (involves factoring)?

Question

Suppose the equation is the following:

x(x+5)(x+35)=2,000

How would you go about solving for x?

I am aware that the answer would be 5, but I need the algebraic work proving it.

Answer 1

5(5+15)(5+15)=2000

(5 times 20=100) and (100 times 20 =2000)

So all those X's = 5

Answer 2

You can unfactorize to thies: x^3+40x^2+175x-2000=0

or taking into consideration you have x+5 and x+35, you can test eathier values... 5 or 35 must be a possible value of x.

If you change X for 35 and do the operations you will not reach 2000.

But... if you change X fo 5, the total will be 2000.

Answer 3

Multiply it out:
You get x³ +40x² + 175 x-2000 = 0.
Now any root of this equation is a divisor of 2000,
so we try them and find that x = 5 is a solution.
That means x-5 is a factor and
by long division or synthetic division
we find that the quotient is
x² +45x + 400.
Now we set this equal to zero and solve.
We find
x = ½(-45 + √ 425)
and x = ½(-45 - √425).
Hope that helps!

Answer 4

You do something suggested as Factoring through grouping on the first one you're making it (2x^3 - 24x^2) - (3x+36) Pull out the impressive person-pleasant element for each parenthesis 2x^2 (x-12) -3 (x-12) You pull out the (x-12) because that is the impressive person-pleasant element of the completed element in case you do not have a impressive person-pleasant element there then you fairly did something incorrect. which makes it (2x^2 -3)(x-12) on the bonus question you do the same element. i imagine the answer is 5x(x-2)(x+2)(4x-a million)

Answer 5

Distrubutive Property of all the numbers in the ()'s and the simplify

Answer 6

i hope you dont mean that question...lol