2 LiOH + CO2 ---> Li2CO3 + H20 what mass ofcarbon dioxide can 1000g of lithium hydoxide absorb?

Question

also what mass of lithium carbonate, Li2CO3 is produced?

need a lil help im lost as lost can be lol

Answer 1

From your balance reaction equation, two moles of LiOH will absorb one mole of CO2. Convert grams of LiOH to moles: the molecular mass of LiOH = 24, so 1000g of LiOH is 41.67 moles. This will produce 41.67/2 = 20.83 moles of CO2. The molecular mass of CO2 is 44, so 20.83 moles of CO2 = 44*20.83 = 916.67g of CO2. The same reaction will produce the same no of moles of Li2CO3 as moles of CO2. So there will be 20.83 moles of Li2CO3 produced. The molecular mass of Li2CO3 is 74, so 74*20.83 = 1541g of Li2CO3. (I used round numbers for molecular masses; you can get more exact quantities by looking up their molecular masses in a handbook.)

Answer 2

First convert the 1000g of LiOH into moles by dividing the grams by the grams formula mass. I got 41.67 moles. Then set up a ratio using the coefficients in the reaction.

2/41.67 = 1/x
This will give you the moles of Li2CO3. You will have to convert it into grams for the mass.

Answer 3

GFM LiOH = A
GFM CO2 = B (cant find my data booklet so using letters)

2 LiOH can absorb 1 CO2
2x (A)g can absorb 1x (B)g

I always take the calculation back to 1.

1g LiOH --> A/B

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1000g LiOH = A/B * 1000.
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The part where you want to know the mass of Li2Co3 produces is too much for me.