2007-04-27 08:56:18 · 31 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
820
2007-04-27 08:59:09 · answer #1 · answered by San 2 · 0⤊ 5⤋
so the question is: (55+ 5-15+9+110)(-5)? if so than the answer is -820.
Or if the question is (55+5-15+9)+(110x-5), than the answer is
54 + 550 = -604
However, if the negative sign after the last five is a typo than the anwes are positive 820 or 604 respectively.
2007-04-27 09:10:42 · answer #2 · answered by davidjohncpa 2 · 1⤊ 1⤋
604
Math rules say that you do the multiplication before the addition and subtraction:
55 + 5 -15 +9 +110 x 5
= 55 + 5 -15 + 9 + 550
2007-04-27 09:04:25 · answer #3 · answered by Simon T 6 · 4⤊ 0⤋
55+5-15+9+110x5
=54+550
=604
2007-04-27 21:30:14 · answer #4 · answered by gudspeling 7 · 2⤊ 0⤋
55 + 5 = 60
60 - 15 = 45
45 + 9 = 54
110 * 5 = 550
550 + 54 = 604
2007-04-28 03:43:09 · answer #5 · answered by crazychick_woman 4 · 1⤊ 0⤋
55+five-15+nine+110xfive
= 55-15+110xfive+five+nine
= 40+ five(110+1)+nine
=40 + 111five + nine
=604
or
= six zero four
but if you meant: five- = -5
=55+five-15+nine-110xfive
= 55-15-110xfive+five+nine
= 40+ five(-110+1)+nine
=40 - 109five + nine
= -496
or
= four nine six -
note: first do 110xfive
2007-04-27 09:51:57 · answer #6 · answered by Anonymous · 2⤊ 0⤋
820
2007-04-30 22:42:47 · answer #7 · answered by Falcon Feather 2 · 0⤊ 0⤋
820
2007-04-30 08:33:02 · answer #8 · answered by Anonymous · 0⤊ 0⤋
604
2007-04-27 09:00:38 · answer #9 · answered by Anonymous · 3⤊ 0⤋
its either 820 or 604. it depends whether or not u do the multiplication before adding (so u add 550) or whether u do the adding (add 110) and then multiply 164 by 5 to give 820.
2007-04-28 01:59:47 · answer #10 · answered by nfslpu 2 · 0⤊ 1⤋
My answer to a normal maths question would be 820 (60-15 =45 +9=54+110=164x5=820) but I feel this is a bit of a trick question and there is some significance with every other number being expressed in letters - or am I reading too much into simple mental arithmatic?
2007-04-27 09:06:52 · answer #11 · answered by Anonymous · 0⤊ 5⤋