Failure of steel tubular column due impact force of a falling object?

Question

The object falls on one edge of the vertical tubular column. What I wish to know is what is the mechanics of the failure and what forces are involved. Does the column fail because of a compressive force causing brittleness or that the forces involved exceed the tensile strength.

How can the impact force be calculated and where can I find information about the limiting forces for failure of the materiel of the column in such a situation. Please note I work in the metric system.

Answer 1

The column fails as the result of two types of loading.

The first is the compressive stress on the entire cross section of the column due to the force of the weight that falls on it.

The second stress is the compressive bending stress in the column because the force of the weight is striking it off center.

You combine those two stresses to get the total maximum compressive stress.

The allowable stress is the allowable buckling stress for the column.
Although you do not give the length of the column you would have to calculate the L/r ratio for the column = Length in inches/radius of gyration in inches for the columns section.
Then you go thru the exersize of calculating the allowable buckling stress due to direct compression and bending.

Answer 2

Ahh the previous impression tension question. 1st) Your lacking techniques such as a results of fact the time it takes from the 2d of impression to the 2d of relax. 2d) this question is designed to weed out the theory that when all forces stability out, an merchandise would desire to be at relax. So the 1st tension, weight, is balanced with the aid of the 2d tension, established tension (at impression), therefor the falling merchandise would desire to end excellent? incorrect, this is called inertia. skill that on the time the equalizing tension became into utilized the object stopped accelerating it somewhat is it. So you may now desire to calculate the tension it takes to deliver it back to sit down down back. F=ma =(weight/gravity) * (Vimpact - 0)/(TIME from impression to sit down down back). Assuming no bounceback of course, and watch your gadgets. the significant element is comprehend what inertia is. IMO :) I edited "distance" would desire to be "time"