The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet then what are the

Question

The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet then what are the length and width?

Answer 1

x+50=y --->eqn 1
where y is the length and x is the width

2x+2y=500--> eqn2

sub y=x+50 into eqn2,

2x+2(x+50)=500
2x+2x+100=500
4x=500-100=400
x=100

sub x=100 into y=x+50,
we get y=100+50=150

thus x=100 (width) and y=150(length)

Answer 2

The length would be 150 and the width 100. Simple equation of 2x + 2(x+50)=500. Solve for x which is your width and the x+50 is your length.

Answer 3

Let y = width

Then length = y + 50

Perimeter of a rectangle = 2*width + 2*length.

500 = 2y + 2(y+50)

500 = 4y + 100

subtract 100 from both sides

4y = 400

divide through by 4

y = 100 ft (width)

y + 50 = 150 ft (length)

Answer 4

2(length) + 2 (width) = perimeter

length = width + 50

2(w+50) + 2(w) = 500

2w + 100 + 2w = 500

(2w + 2w) = 500 - 100

4w = 400

4w/4 = 400/4

w = 100

l = 100 + 50

l = 150

width is 100feet and length is 150feet

Answer 5

x the length
y the width

x + 50 = y
2x +2y = 500 => x+y=250

=> 2x + 50 = 250 x=100 => y=150

Answer 6

l = length
w = width

From the question

l = w +50

l + l + w + w = 500 or 2l =2w = 500

but l=w+50, so substitute for l

2(w+50) +2w = 500 expands to 2w +100 +2w = 500

combine the ws and subtract 100 from each side:
4w=400
so
w=100 l=150

Answer 7

L = 50 + w

Perimeter = 2(L + w) = 500
2(50+w + w) = 500
2(50 + 2w) = 500
100 + 4w = 500
4w = 400
w = 100 ft
L = 150 ft

Answer 8

l=length, w=width

l=w+50

perimeter=2l+2w=500

substitute: 2(w+50)+2w=500

4w+100=500
4w=400

w=100
l=150