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what is the wavelngth of 47.2 GeV electrons?

2007-04-27 06:21:11 · 1 answers · asked by Syliva P 1 in Science & Mathematics ➔ Physics

1 answers

Planck constant in terms of eV:
4.13566733 x 10-15 eV-seconds

E = h * (c / lambda)

47.2 * 10^9 = (4.135*10^-15) * (3*10^8) / lambda

lambda = 2.63 * 10^-17 meters = 26.3 attometers

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2007-04-27 06:31:53 · answer #1 · answered by tlbs101 7 · 0⤊ 0⤋

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