2007-04-27 06:07:14 · 10 answers · asked by Jameela S 1 in Science & Mathematics ➔ Mathematics
4 possible outcomes. HT, HH, TH, TT
Prob(TT)=1/2 * 1/2 =1/4
2007-04-27 06:12:28 · answer #1 · answered by (^InLove^) 3 · 1⤊ 0⤋
4 to 1
2007-04-27 06:17:31 · answer #2 · answered by omvg1 5 · 0⤊ 0⤋
if it is a two tailed coin then the answer is 1, otherwise given a boring old lincoln penny, the probability of no heads after two measly tosses is 1/2 * 1/2 = 1/4.
1/4 of the time, lincoln's bearded face will not appear.
2007-04-27 06:51:14 · answer #3 · answered by Anonymous · 0⤊ 0⤋
p(neither shows heads) = p( 1st t) X p( 2nd t)
= 1/2 x 1/2
= 1/4
2007-04-27 06:16:11 · answer #4 · answered by harry m 6 · 0⤊ 0⤋
There are four possibilities:
H H
T H
H T
T T
If neither is a head, then both must be tails.
So the probability is 0.25 or 1/4
2007-04-27 06:17:40 · answer #5 · answered by Robert L 7 · 0⤊ 0⤋
1/4 or 25%
2007-04-27 06:20:28 · answer #6 · answered by Nandan Kavan 1 · 0⤊ 0⤋
truly no longer 2. you are able to basically provide a significant answer for a finite sport. opt for any reduce in words of optimal type of performs or optimal payout, after that you will be able to calculate a honest value. application isn't appropriate to this honest (ruin-even) value. extremely, that is a way of quantifying possibility aversion. it might want to help me calculate the minimum i might want to charge over the honest fee in the previous i'm keen to bankroll the game.
2016-11-28 02:49:54 · answer #7 · answered by fredline 4 · 0⤊ 0⤋
p=.25, since the sample space consists of the four equally likely out comes HH, HT, TH, TT.
2007-04-27 06:11:57 · answer #8 · answered by helper 7 · 1⤊ 0⤋
1/4...
2007-04-27 06:09:47 · answer #9 · answered by Jedi squirrels 5 · 3⤊ 1⤋
25% or .25
2007-04-27 06:10:24 · answer #10 · answered by jimbob 6 · 2⤊ 1⤋