Calculus question....?

Question

I should know how to do this but for some reason I'm drawing a blank. I have a final this afternoon and need to know how to determing what the x and y intercepts of this function are. So please help me out. I dont just need the answer, but the process as well.

What is the y intercept of x^3-6x^2 and how do I find that?

What are the x intercepts of x^3-6x^2 and how do I find them?

Answer 1

y=x^3-6x^2

You get the y-intercept when the function crosses x=0 (which is the y-axis) so y(0)=0

The x itercept is when the function crosses the y axis (which is the x-axis) this is another way of asking for the zeroes of a function

y(x)=x^3-6x^2=0

factor y so y=x^2(x-6) so y=0 when x=0 (a double root since the term is x^2) and x=6 is the other root since x-6=0.

Answer 2

Calculus question....?
I should know how to do this but for some reason I'm drawing a blank. I have a final this afternoon and need to know how to determing what the x and y intercepts of this function are. So please help me out. I dont just need the answer, but the process as well.

What is the y intercept of x^3-6x^2 and how do I find that?put x=0, it gives zero.So the intercept on the y-axis is zero

What are the x intercepts of x^3-6x^2 and how do I find them?
put x=0, it gives 0,so the intercept on the y -axis is zero.pu y=0, then x=0,6, so intercept on the x-axis is zeroor 6.

Answer 3

First of all, it's easiest to factor first:
x^3-6x^2
=x^2(x-6)

The y-intercept is where the function crosses the y-axis, so x=0 at that point. You substitute 0 for x:

y=x^2(x-6)
y=0^2(0-6)
y=0
The y-intercept is the point (0,0) (we set x=0 and got y=0)

The x-intercept is where the function crosses the x-axis, so y=o at that point. You substitute 0 for y:

y=x^2(x-6)
0=x^2(x-6)
{x^2, x-6} = 0
x=0, x=6

There are two x-intercepts, one with an x-coordinate of 0, and one with x-coordinate of 6. Thus, they are (0,0) and (0,6).

Answer 4

hi.
1)to find y-intercept u should replace the x with zero

in this case y intercept = 0

2- to find x-intercept u should make the function =0
in this case:
x^3-6x^2=0

(x^2)*(x-6)=0

that means we have to x intercepts
at x=0 and x= 6

hope u will understand.

Answer 5

Question 1
y = x² (x - 6)
When y = 0:-
x = 0, x = 6
Intercepts are (0,0) and (6,0)
y intercept is (0,0)
x intercepts are (0,0) and (6,0)