i have a question with lambda = mean free path and it says at what pressure does the mean free path of argon at 25 celculis become comparable to 10 times the diameter of the atoms themselves with o=0.36nm^2?
****and then in the answer it says diameter = (0.36nm^2/1)^.5 but then they get the answer 3.39x10^-10 is the equation wrong i think it has something to do with being divided by 1? i dont think im reading it correctly. can someone tell me this expression for diameter of an atom? thanks
2007-04-27 03:45:56 · 1 answers · asked by bunnylover1987 1 in Science & Mathematics ➔ Chemistry
√(0.36nm^2/π) ≈ 0.33851 nm ≈ 3.3851*10^-10 m, so o=0.36nm^2 must refer to the collision cross-section of the atom, which is π(2r)^2, or πd^2. Using this assumption, 3.3851*10^-10 m is the diameter of the atom.
2007-04-27 17:52:51 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋