Im not particularily sure how to answer this question, is it as simple as 95-32=63 or am i missing something?
2007-04-27 03:36:46 · 8 answers · asked by lily paige 2 in Science & Mathematics ➔ Mathematics
F = (9/5)C + 32
so... for C = 95
F = (9/5)(95) + 32
= 9(19) + 32
= 171 + 32
= 203
2007-04-27 03:41:33 · answer #1 · answered by Mathematica 7 · 1⤊ 1⤋
A symmetrical conversion, based on the fact that
-40degC = -40degF:
Add 40.
Multiply by 5/9 to convert from F to C, or by 9/5 to convert from C to F.
Subtract 40.
For c = 95:
f = (95 + 40)*9/5 - 40
= 135*9/5 - 40
= 27*9 - 40
= 243 - 40
= 203.
2007-04-27 11:06:00 · answer #2 · answered by Anonymous · 1⤊ 0⤋
The way I learned it was C * (9/5) + 32 = F
9/5 = 1.8 in decimal system
So that would make the calculation:
95 * 1.8 = 171 + 32 = 203
If C = 95 then F = 203
2007-04-27 10:43:59 · answer #3 · answered by Shannen D 2 · 1⤊ 0⤋
Fahrenheit : Celcius : Reamur = 9 : 5 : 4
Known:
Celcius (C) = 95
Unknown:
Fahrenheit (F)
Solution :
F = 9/5*C + 32 (formula)
F = 9/5*95 + 32
F = 171 + 32
F = 203
2007-04-27 10:43:49 · answer #4 · answered by bobang 2 · 1⤊ 0⤋
F=9/5C+32
C=5/9(F-32)
2007-04-27 11:10:05 · answer #5 · answered by none 2 · 1⤊ 0⤋
Fahrenheit Formula
F = 9/5C + 32
F = 9/5(95) + 32
F = 855 / 5 + 32
F = 171 + 32
F = 203°
- - - - - - - - -
Celsius Formula
C = 5/9(F - 32)
C= 5/9(- 32 - 32)
C = 5/9( - 64)
C = - 320 / 9
C = 35.555555555°. . .
- - - - - - - - -s-
2007-04-27 11:00:14 · answer #6 · answered by SAMUEL D 7 · 2⤊ 0⤋
Yes : multiply by 9/5 and add 32
eg. 95C = 95*9/5 + 32 = 204F
e.g. 20C = 20*9/5 + 32 = 68F
2007-04-27 10:40:09 · answer #7 · answered by welcome news 6 · 1⤊ 0⤋
C=95 degrees
Here's the formulas:
C=5/9F-32
F=9/5C+32
F=9/5C+32
F=9/5(95)+32
F=171+32
F=203 degrees
2007-04-27 11:37:02 · answer #8 · answered by Anonymous · 0⤊ 0⤋