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Working in the dark, you sprinkle negative charge onto this surface. If you now expose only the left half of the photoconductor to light what will happen?

2007-04-27 02:53:02 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Electrons will be emitted on the lighted side and a redistribution of charge will take place.

2007-04-27 21:39:38 · answer #1 · answered by ag_iitkgp 7 · 0 0

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