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a manufacturer of two models of wok has determined that the profit from work A is $15 and the profit for B is $20. the manufacturer can produce no more than 200 woks per week. to meet the market demand, at least 50 wok A must be made and 100 of Wok B must be available for sale each week. find the number of woks A and B that would lead to the maximum profit

2007-04-26 21:36:24 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

50WokA x$15 profit=$750
150WokB x $20profit=$3000
Total=$3,750

2007-04-26 21:45:24 · answer #1 · answered by pawpaw 1 · 0 0

For maximum profit the manufacturer would want to make 200 B's, but has to make 50 A's, so can only make 150 B's.

2007-04-27 04:51:25 · answer #2 · answered by Helmut 7 · 0 0

you can frame a linear programming problem to solve this.
first make the constraints:
Work A-x
Work B-y

x+y x>or=50 y>or=100

plot these lines on a graph and solve it.
to solve: substitute any abitrary point and verify the truth of the equation ie if x,y=0 and u put it in the first eq the statement becomes true ie 0<200. in ur mind shade the region towrd the origin and solve the other eqs and find a common area.
Ascertain the coordinates of the points bounding the region and substitute it in z=15x+20y since that is the profit.
the coordinates for which u get the highest value of Z is the number he must produce.

2007-04-27 04:50:33 · answer #3 · answered by Titan 4 · 0 0

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