Factoring Trinomials (When a = 1)?
1: x2 - 8x + 16
(x - 8)(x - 2)
(x - 4)(x - 4)
(x - 4)(x + 4)
2: x2 + 8x - 48
(x + 12)(x - 4)
(x + 8)(x + 6)
(x + 8)(x - 6)
3: x2 - 6x - 16
(x - 4)(x - 4)
(x + 4)(x - 4)
(x - 8)(x + 2)
4: x2 - 2x - 48
(x - 12)(x + 4)
(x + 6)(x - 8)
(x - 6)(x - 8)
5: x2 + 14x + 33
(x + 11)(x + 3)
(x - 11)(x + 3)
(x + 33)(x + 1)
6: x2 - 2x + 1
(x - 1)(x + 1)
(x - 2)(x - 1)
(x - 1)(x - 1)
7: x2 - 5x + 4
(x - 1)(x - 4)
(x - 1)(x + 4)
(x - 2)(x - 2)
8: x2 - 10x - 11
(x - 11)(x - 1)
(x - 11)(x + 1)
(x + 11)(x + 1)
9: x2 - 11x + 30
(x - 5)(x - 6)
(x + 3)(x - 10)
(x - 3)(x - 10)
10: x2 - 9x - 10
(x - 5)(x + 2)
(x + 5)(x - 2)
(x + 1)(x - 10)
11: x2 - 4x - 5
(x + 1)(x - 5)
(x - 1)(x - 5)
(x - 1)(x +5)
12: x2 - 8x + 15
(x - 3)(x - 5)
(x - 15)(x - 1)
(x + 3)(x + 5)
13: x2 + 13x + 42
(x + 21)(x + 2)
(x + 2)(x - 21)
(x + 7)(x + 6)
14: 2x2 - 32x + 128
2(x - 16)(x - 4)
2(x - 8)(x - 8)
2(x - 2)(x + 32)
15: 2x2 + 4x - 198
2(x - 9)(x - 11)
2(x - 2)(x + 11)
2(x - 9)(x + 11)
2007-04-26 21:22:31 · 7 answers · asked by laney s 1 in Science & Mathematics ➔ Mathematics
do your own homework
2007-04-26 21:25:21 · answer #1 · answered by Anonymous · 1⤊ 1⤋
1.(x - 4)(x - 4)
2.(x + 12)(x - 4)
3.(x - 8)(x + 2)
4.(x + 6)(x - 8)
5.(x + 11)(x + 3)
6.(x - 1)(x - 1)
7.(x - 1)(x - 4)
8.(x - 11)(x + 1)
9.(x - 5)(x - 6)
10.(x + 1)(x - 10)
11.(x + 1)(x - 5)
12.(x - 3)(x - 5)
13.(x + 7)(x + 6)
14.2(x - 8)(x - 8)
15.2(x - 9)(x + 11)
2007-04-27 08:11:39 · answer #2 · answered by sejal aka shortee 2 · 0⤊ 0⤋
1.(x - 4)(x - 4)
2.(x + 12)(x - 4)
3.(x - 8)(x + 2)
4.(x + 6)(x - 8)
5.(x + 11)(x + 3)
6.(x - 1)(x - 1)
7.(x - 1)(x - 4)
8.(x - 11)(x + 1)
9.(x - 5)(x - 6)
10.(x + 1)(x - 10)
11.(x + 1)(x - 5)
12.(x - 3)(x - 5)
13.(x + 7)(x + 6)
14.2(x - 8)(x - 8)
15.2(x - 9)(x + 11)
2007-04-27 04:44:06 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
The factoring has already been done for you. All you need do is choose the correct factors. If you can't do this by inspection, multiply them out to see which is right.
2007-04-27 04:33:57 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
gold star for you
well done
2007-04-27 04:33:42 · answer #5 · answered by 5hell 2 · 0⤊ 0⤋
1:(x-4)(x-4)
2:(x+12)(x-4)
3:(x-8)(x+2)
4:(x+6)(x-8)
5:(x+11)(x+3)
6;(x-1)(x-1)
7;(x-1)(x-4)
8;(x-11)(x+1)
9;(x-5)(x-6)
10;(x+1)(x-10)
11;(x+1)(x-5)
12;(x-3)(x-5)
13;(x+7)(x+6)
14;2(x-8)(x-8)
15;2(x-9)(x+11)
2007-04-27 04:44:41 · answer #6 · answered by py 2 · 0⤊ 0⤋
looks like he/she did
2007-04-27 04:27:26 · answer #7 · answered by whatcanmaxdo4u?everythingupscant 3 · 0⤊ 1⤋