(3x + 2) - (2x - 3) =?
I'm not in school right now, so I'm not cheating or anything. This problem appeared on a forum I post on and we're all stuck on how to solve it. I got this:
x = -5 +/- the sq. root of 15 over -12
I used quadratic formula. I guess thats how to do it, but I don't know. I'm probably WAY off. Any help?
2007-04-26 19:25:26 · 12 answers · asked by nicodemoscain 2 in Science & Mathematics ➔ Mathematics
That is a minus sign between the two sets of numbers.
2007-04-26 19:30:57 · update #1
(3x +2) - (2x - 3)
= 3x+2 - 2x + 3
= x + 5.
If the given expression is = 0 then
x + 5 = 0
=> x = - 5.
2007-04-26 19:57:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Your question is not clear.
Perhaps the sign between the parenthesis should be a product sign. That's the only way you'll end up with a quadratic expression.
(3x + 2)*(2x - 3) = 6x^2 - 5x - 6. That is not an equation. To use the quadratic equation, that must be set equal to some value. If that value is 0, you don't need the quadratic equation since the expression is given in factored form.
(3x + 2)*(2x - 3) = 0 has solutions for x when each of the factors is zero, or
(3x + 2) = 0 and (2x - 3) = 0
You can solve each of these to get x = -2/3 and x = 3/2
2007-04-27 02:33:13 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
well, in order to solve for x, you have to set that equation equal to 0, then distribute the negative sign to the 2x and 3...so it will be
3x + 2 - 2x + 3 = 0
then....x +5 = 0
then x = -5
2007-04-27 02:33:12 · answer #3 · answered by rubiks87 2 · 0⤊ 0⤋
x=-5 /1 the square root of 15 over -12= -4 the square root of 15 over -12 (reduce)= -1 the square root of 15 over -3
square roots do not go into whole numbers.
If you use polynominals it would be FOIL first , outside , inside , last multply it out then add it up.
6x2+9x-4x+6=6xto the second power+5x+6
2007-04-27 02:53:47 · answer #4 · answered by Kandice F 4 · 0⤊ 0⤋
"I'm assuming you mean:
(3x + 2)(2x-3)
Use FOIL which means First Outer Inner Last
1. multiply the first two terms 3x and 2x= 6x^2
2. mutliply the outers 3x and 3= -9x
3. mutliply the inners 2 and 2x= 4x then add that to the product of the outers= -9x +4x = -5x
4. then multiply the lasts 2 and -3= -6
write it all out
6x^2-5x-6"
Props to Gweengrl89. Same problem, different question.
2007-04-27 02:29:45 · answer #5 · answered by Kacee 3 · 0⤊ 0⤋
3x + 2 -2x +3 = 0
x = - 5
2007-04-27 02:30:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the answer is -5
(3x+2)-(2x-3)=0
3x+2-2x+3=0
3x-2x+2+3=0
x+5=0
x=-5
You would only use the quadratic formula if the equation was
(3x+2)(2x-3) or in this form: x^2+x+2
2007-04-27 02:34:34 · answer #7 · answered by spiman985 1 · 0⤊ 0⤋
(3x + 2) - (2x - 3)
= 3x + 2 - 2x + 3
= x + 5
Notice the sign change as negative multiplied by negative, it become positive.
2007-04-27 02:30:54 · answer #8 · answered by helping_people 2 · 0⤊ 0⤋
X = -5.
2007-04-27 02:31:28 · answer #9 · answered by Dave R 2 · 0⤊ 0⤋
without a sum for ? you can't get an absolute value for x.
how about this
3x+2-2x+3=?
x+5=? or x=?-5
2007-04-27 02:32:37 · answer #10 · answered by racer_rik 2 · 0⤊ 0⤋