2007-04-26 17:53:57 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Do you mean by 2*4^(a+1)=8?
If that is your question, the solution is:
4^(a+1)= 8/2
4^(a+1)=4
4 is also known as 4^1
thus 4^(a+1)=4^1
Comparing coefficients of powers,
(a+1) = 1
a=1-1=0
2007-04-26 18:02:53 · answer #1 · answered by (^InLove^) 3 · 0⤊ 0⤋
2*4^(a+1) = 8 divide both sides by 2
4^(a+1) = 4 so a+1 must be equal to 1
a+1 = 1 subtract 1 from both sides
a = 0
HTH
Doug
2007-04-27 01:01:25 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
2*4^(a+1) = 8
First multiply 2 by 4 you will get:
8^(a+1) = 8
The 8 to the right actually has the power of 1 so you can rewrite the equation as:
8^(a+1) = 8^1
So we have:
a+1 = 1
Therefore:
a = 0
Good luck.
2007-04-27 01:07:21 · answer #3 · answered by ¼ + ½ = ¾ 3 · 0⤊ 0⤋
2*4powa+1=8
4^(a+1) = 4
a+1=1
a=0
2007-04-27 01:01:45 · answer #4 · answered by glade_moonstone 3 · 0⤊ 0⤋
2 * 4^(a + 1) = 8
4^(a + 1) = 4
(a + 1) log4 = log4
a + 1 = 1
a = 0
now if you meant:
2 * 4^a + 1 = 8
2 * 4^a = 7
4^a = 7/2
a log4 = log(7/2)
a = log(7/2)/log4 = 0.9
2007-04-27 01:07:02 · answer #5 · answered by Anonymous · 0⤊ 0⤋
2*4^(a+1)=8
4^(a+1)=4
4^(a+1)=4^1
a=0
2007-04-27 01:05:01 · answer #6 · answered by azn_drgn_125@sbcglobal.net 1 · 0⤊ 0⤋
4^a = 7/2 = 3.5
a = ln(3.5)/ln(4)
2007-04-27 01:03:15 · answer #7 · answered by Anonymous · 0⤊ 0⤋
a=0.9036775
2007-04-27 01:15:32 · answer #8 · answered by Ralph 1 · 0⤊ 0⤋