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the diagonals of a parallellogram are 82 and 30 cm. one altitude is 18 cm long. find the two possible values for the area.

2007-04-26 17:06:25 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

there are no sides and its solvable

2007-04-26 17:59:30 · update #1

3 answers

There you go, hope it helps:

http://img250.imageshack.us/img250/3518/paralelogramcopynq8.jpg

Any doubts just tell me.

[edit] well, i'll be! I can't sum 80 plus 24 properly! Please follow Northstar's correction. Thanks Northstar!

2007-04-26 18:14:51 · answer #1 · answered by Ferts 3 · 0 0

Ferts has a great diagram and his methodology is correct. He just has a little arithmatic error.

You have two right triangles and when you add the bases together you get twice the length of the parallelogram.

Triangle 1.

y² = 82² - 18² = 6400
y = 80

Triangle 2.

x² = 30² - 18² = 576
x = 24

Let
L = length of parallelogram
A = area of parallelogram
h = altitude of parallelogram

2L = x + y = 80 + 24 = 104
L = 104/2 = 52

A = Lh = 52*18 = 936 cm²

2007-04-27 03:55:00 · answer #2 · answered by Northstar 7 · 0 0

we get a definite value that is are of parallelogram=1008
For further details mail me at sabrinabgs@yahoo.com.sg
thanks for the 2 points too.

2007-04-27 00:44:19 · answer #3 · answered by Sharon 2 · 0 1

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