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A 63.8 kg canoeist stands in the middle of her canoe. The canoe is 3.6 m long, and the end that is closest to land is 2.5 m from the shore. The canoeist now walks toward the shore until she comes to the end of the canoe. Suppose the canoeist is 3.4 m from shore when she reaches the end of her canoe. What is the canoe's mass?

2007-04-26 16:34:53 · 1 answers · asked by Dan 1 in Science & Mathematics Physics

1 answers

If there is no friction in the water, then the center of mass will remain constant. Using the shore as a reference x=0

(63.8+m)*(2.5+3.6/2)=
63.8*3.4+m*(3.4+3.6/2)

(63.8+m)*4.3=63.8*3.4+m*5.2
m*(5.2-4.3)=63.8*(4.3-3.4)
m=63.8*1.1/.9
m=63.8*1.1/.9
m=77.8 kg

j

2007-04-27 07:26:29 · answer #1 · answered by odu83 7 · 0 0

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