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A 15.0 g marble is dropped from rest onto the floor 1.39 m below.

(a) If the marble bounces straight upward to a height of 0.580 m, what is the magnitude and direction of the impulse delivered to the marble by the floor? (Use a positive sign for the up direction, negative for down.)

2007-04-26 16:31:43 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

v1 = - √2*1.39*9.81 = - 5.2222
v2 = √2*0.58*9.81 = 3.3734
I = 15(3.3734 + 5.2222)/1,000
I = 0.128934 Nm/s

2007-04-26 16:46:31 · answer #1 · answered by Helmut 7 · 0 0

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