Radiation of a bulb?

Question

An incandescent lightbulb has a tungsten filament that is heated to a temperature of 3 × 103 K when an electric current passes through it. If the surface area of the filament is approximately 1.00 × 10-4 m2 and it has an emissivity of 0.36, what is the power radiated by the bulb?

Answer 1

Power radiated by the bulb is
P=e b A T^4
Where
Emissivity e=.36
Boltzmann’s Constant b = 5.670 E−8 W/•m^2•K
Area in question A=1.00 E-4 m^2
Temperature in question T=3 E+3 K
P=e b A T^4
P=0.36 x 5.670 E−8 x 1.00 E-4 x (3 E+3 )^4
P= 165 Watts