Are the expressions 2X(X+4) and X^2+X^2+4X are the same, please explain. Thanks.
2007-04-26 15:06:41 · 23 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If your expression is
2x(x+4)
Then distribute the 2x
=2x*x+2x*4
=2x^2+8x
So no, they are not equivalent
note: many people are saying the expressions are equivalent, but they must've forgotten the 2 when they distributed
2007-04-26 18:22:37 · answer #1 · answered by Jim 5 · 0⤊ 0⤋
1) 2X(X+4) and X²+X²+4X
If 2 times (x+4)and x² + x² +4x =
(x+4) + (x+ 4) and 2x² + 4x
2x + 8 is different of 2x² + 4x
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2)
If2x(x + 4) and x² + x² + 4x
2x² + 8x is different of 2x² + 4x too.
So, there is no equality between the two equations.
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2007-04-26 23:03:12 · answer #2 · answered by aeiou 7 · 2⤊ 0⤋
Nope, real close though... if you distribute (multiply the 2x through the parenthesis) you would get 2x^2 + 8x. 2x^2 is the same as x^2 + x^2 but we are missing 4x. A common mistake when distributing is to multiply only the first term of the parenthesis. This is pretty much what happened here.
2007-04-26 22:13:10 · answer #3 · answered by JirafaBo 2 · 2⤊ 0⤋
No, because using the distributive property 2X(X+4) would equal 2X^2 + 8X while the other expression simplified is 2X^2 + 4X.
2007-04-26 22:10:44 · answer #4 · answered by kingliness 2 · 4⤊ 0⤋
Uhm, actually no, I don't think they are equal. In the first expression if you distribute the 2x you get 2x^2+8x. In the second expression if you simplify then you get 2x^2+4x.
2007-04-26 22:11:57 · answer #5 · answered by becca h ♥ 2 · 3⤊ 0⤋
No because if you distribute the 2x to (x+4) your answer is
2x*2+8x
and x*2+x*2+4x is
2x*2+4x
is you distribute that your answer would be
2x(x+2)
2007-04-26 22:13:23 · answer #6 · answered by Katie C 2 · 2⤊ 0⤋
No. The first expression is simplified to X^2 + X^2 + 8x not 4x by the distributive property. Therefore they are not the same.
2007-04-26 22:11:11 · answer #7 · answered by thj1313 2 · 4⤊ 0⤋
2x(x+4)
...multiplied out yeilds:
2x(x) + 2x(4)
2x^2 + 8x
______________________________
x^2 + x^2 +4x
... summed out reveals:
2x^2 + 4x
______________________________
(2x^2 + 8x) does Not equal (2x^2 + 4x).
Let us substitute the value 1 for x:
[2(1)^2 + 8(1)] â [2(1)^2 + 4(1)]
[2 + 8] â [2 + 4]
[10] â [6]
No, the two expressions are not the same.
2007-04-26 22:31:01 · answer #8 · answered by TrudyB-119 1 · 2⤊ 0⤋
No,
2x(x+4) is 2x^2+8x if you expand it, use the distrubutive property.
x^2+x^2=2x^2 the next term is 4x.
8x is not equal to 4x.
2007-04-26 22:14:48 · answer #9 · answered by lulu 3 · 2⤊ 0⤋
The left hand side is 2x^2 + 8x. The right hand side is 2x^2 +4x. Hence they are not equal
2007-04-26 22:11:22 · answer #10 · answered by dodgetruckguy75 7 · 4⤊ 0⤋