sin(90-x) = cos x for all x
Therefore cos x = 0.5
2007-04-26 13:33:49
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answer #1
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answered by gudspeling 7
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Let' s expand sin(90-x)= sin 90 cos x - cos 90 sin x.
Since sin 90 = 1 and cos 90 = 0 (I assume
you are in degree mode.)
We get cos x. So cos x = 0.5.
You could also get this result by comparing
the 2 acute angles of a right triangle.
2007-04-26 14:18:12
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answer #2
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answered by steiner1745 7
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the sin of 30 equals .5 thus 90-x=30. So, x=60. Thus, the cos of 60 is .5
2007-04-26 13:29:14
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answer #3
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answered by Anonymous
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okay, so obviously you are in degree mode. so, remember that the value at which sin(x)= 1/2 is at 30 degrees. so, this is tellign you that sin(90-x)=sin(30)
so, x is 60.
therefore, if you take cos(x) when x=60,
then cos(60)=1/2
2007-04-26 13:16:31
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answer #4
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answered by Banjolick 1
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particular. This originates from the essential id sin^2(x)+cos^2(x)=a million observe that if we circulate cos^2(x) term on the different area, we get: => sin^2(x)+cos^2(x)=a million => sin^2(x)=a million-cos^2(x)
2016-10-30 09:39:49
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answer #5
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answered by ? 4
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x would equal 89.5 if that's what you are asking.
I don't think that's even what you are asking though.
2007-04-26 13:12:35
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answer #6
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answered by sara d 2
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cos(x)=0.5
2007-04-26 13:17:32
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answer #7
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answered by Serendipity 1
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