2007-04-26 12:51:44 · 6 answers · asked by Gerrad G 1 in Science & Mathematics ➔ Mathematics
2(2x^2 + 3x -2) / 2x-1
2(2x -1)(x+2) / 2x - 1
2(x+2) or 2x+4
2007-04-26 12:55:05 · answer #1 · answered by richardwptljc 6 · 0⤊ 0⤋
first, look at the top: 4x^2+6x-4
that can be factored out to be: (2x-1)(2x+4)
so now it looks like this:
((2x-1)(2x+4))/ (2x-1)
the (2x-1) cancel out and you're left with:
2x+4
2007-04-26 19:56:12 · answer #2 · answered by reader27 2 · 0⤊ 0⤋
4x^2+6x-4/2x-1
(2x-1)(2x+4)/2x-1
The 2 (2x-1) cancel out
answer is 2x+4
2007-04-26 20:03:22 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(4x^2+6x-4)/(2x-1)
={2(2x^2+3x-2)}/(2x-1)
={2(2x^2+4x-x-2)]/(2x-1)
=[2{2x(x+2)-1(x+2)}] /(2x-1)
={2(x+2)(2x-1)}/(2x-1)
=2(x+2)ans [cancelling 2x-1 of the numerator and denominator]
2007-04-26 20:57:05 · answer #4 · answered by alpha 7 · 0⤊ 0⤋
set it up like you are going to do long division. and then divide. you're gonna get 2x+4.
2007-04-26 19:56:10 · answer #5 · answered by Anonymous · 0⤊ 0⤋
So? What's the operation you want?
2007-04-26 19:55:37 · answer #6 · answered by cattbarf 7 · 0⤊ 0⤋