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How do I factor the following:

6x^3 + 6

5x^2 - 20

x^3 + 2x^2 + 8x + 16

2007-04-26 12:11:42 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

6x^3 + 6
= 6(x^3+1)
= 6(x+1)(x^2-x+1)

5x^2 - 20
= 5(x^2-4)
= 5(x+2)(x-2)

x^3 + 2x^2 + 8x + 16
= x^2(x+2) + 8(x+2)
= (x^2+8)(x+2)

2007-04-26 12:18:28 · answer #1 · answered by Scott R 6 · 0 0

6x^3+6=6(x^3+1)=6(x+1)(x^2-x+1)
5x^2-20=5(x^2-4)=5(x-2)(x+2)

x^3+2x^2+8x+16=(x^2+8)(x+2)

2007-04-26 12:41:20 · answer #2 · answered by Dave aka Spider Monkey 7 · 0 0

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