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Statistics math okay I think I should use but not sure and tried poisson probability but dont know how if you could help. or binomial.

Shutouts in the National Hockey League occur randomly and independently at a rate of 1 every 20 games. Calculate the probability of the following events.

a) 2 shutouts in the next 10 games

b) 25 shutouts in 400 games

c) A shutout in tonight's game

2007-04-26 11:54:42 · 4 answers · asked by wnp46 1 in Science & Mathematics Mathematics

4 answers

Binomial is when you have "n" independent event with a probability "p" of success

p=1/20
p(i) = [n!/(n-i)!*i!] * (p^i) * (1-p)^(n-i)
for a binomial

a) n=10 and i =2
p(2) = [10!/(8!*2!)] * (1/20)^2 * (19/20)^8=0.074635

b) n=400 and i=25
p(25) = [400!/(375!*25!)] * (1/20)^25 * (19/20)^375 = 0.0445527

c)n=1 and i=1
p(1) = [1!/0!*1!] * (1/20)^1 * (19/20)^0 = 0.05

2007-04-26 12:28:29 · answer #1 · answered by MadamX 2 · 0 0

A. 1/20*1/20*10=10/400=1/40
B. (1/20)^25*400=???Don't have a calculator on hand
C. 1/20

Not sure if A and B are right

2007-04-26 11:58:11 · answer #2 · answered by llllarry1 5 · 0 1

a) 45 * [(1/20)^2] * [(19/20)^8]=0.075

b)400choose25 * [(1/20)^25] * [(19/20)^375]
If you have a calculator you can work it out.

c)1/20

2007-04-26 12:17:47 · answer #3 · answered by Anonymous · 0 0

a)
P(2 in 10) = 10C2*0.95^8*0.05^2
P(2 in 10) = 0.07463480

b)
P(25 in 400) = 400C25*0.95^375*0.05^25
P(25 in 400) = (400!/(25!*375!)*0.95^375*0.05^25
P(25 in 400) = 0.04455268

c)
P(1 in1) = 0.05

2007-04-26 12:11:46 · answer #4 · answered by Helmut 7 · 1 0

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