2007-04-26 09:46:02 · 6 answers · asked by Eric M 1 in Science & Mathematics ➔ Mathematics
first simply it as much as possible. you can take out a 5 t^5
so then you have 5t^5 (3t^2 + 10t -25)
then factor (3t^2 + 10t -25)
you get (3t - 5)(t+5)
so your final answer is 5t^5(3t - 5)(t+5)
2007-04-26 09:54:06 · answer #1 · answered by ST 1 · 1⤊ 0⤋
15t^7 + 50t^6 - 125t^5
= 5t^5 (3t^2 +10t - 25)
= 5t^5(3t - 5)(t + 5)
2007-04-26 09:54:25 · answer #2 · answered by need_advice 2 · 1⤊ 0⤋
Factor out a 5t^5:
5t^5(3t^2+10t-25)
5t^2((3t-5)(t+5))
2007-04-26 09:59:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
15t^7-50t^6-125t^5
5t^5(3t^2-10t-25)
5t^5[(3t+5)(t-5)]
2007-04-26 09:54:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
5t^5(3t^2+10t-25)
5t^5(3t-5)(t+5)
2007-04-26 09:54:03 · answer #5 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
5t^5[(3t+5)(t-5)]
2007-04-26 10:01:21 · answer #6 · answered by lass 2 · 0⤊ 0⤋