Chemistry question, net ionic equation?

Question

My chemistry teacher never explained rules for net ionic equations and when i read the text i understood the rules, except in this particular instance as it wasn't specified. write the net ionic equation of the following reaction:
Ca(s) + 2HCl(aq) yields CaCl2(aq) + H2(g)

Answer 1

For the net ionic equation you simply leave out the ions which do not change form in the reaction. In the equation:

Ca(s) + 2 HCl(aq) --> CaCl2(aq) + H2 (g)

The Ca goes from s to aq
the H goes from aq to g
the Cl goes from aq to aq (in other words it does not change)

Rewrite the equation leaving out the ions which do not change - in this case it is the Cl 1- (aq). The ions which do not change are called "spectator ions."

Ca (s) + 2 H 1+ (aq) --> Ca 2+ (aq) + H2 (g)

Answer 2

That relies upon on no matter if the water develop into on the reactant side to boot. i'm assuming that your initial reaction develop into: 3Ca(OH)2(aq) + 2H3PO4(aq) --> Ca3(PO4)2(s) + 6HOH(l) If it really is real, then the water does cancel. usually, Acid-Base reactions do have waters left over. in order to cancel ions in a internet-ionic equation, they should be the same state of be counted, cost, and volume on both aspects. split all the ions to get: 3Ca2+ + 6(OH)- + 6H+ + 2(PO4)3- --> Ca3(PO4)2(s) + 6H+ + 6(OH)- the following, you will discover there are six H+ and six (OH)- ions. The water will cancel. Your internet ionic equation will merely examine: 3Ca2+(aq) + 2(PO4)3-(aq) --> Ca3(PO4)2(s)

Answer 3

Ca(s)+2H+-->Ca2+ +H2