y = (1/3)x + b
-2 = (1/3)(1) + b
-7/3 = b
y = (1/3)x -7/3
2007-04-26 08:40:32
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answer #1
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answered by MamaMia © 7
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y+2= (1/3)(x-1)
2007-04-26 15:42:57
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answer #2
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answered by Kristen 3
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-2=1/3(1)+b
-2 1/3 = b
Equation = Y = 1/3x -7/3
2007-04-26 15:44:27
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answer #3
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answered by EAGLES 3
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Equation: y+2=(1/3)(x-1) or y=(1/3)x-(7/3)
2007-04-26 15:43:48
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answer #4
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answered by HP Fan 2
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y = mx + b
m is slope and b is the x-intercept
y = 1/3 x + b
to find be replace x and y by 1 and -2 respectively
-2 = 1/3 + b
b = -2 - 1/3 = (-6 - 1)/3 = -7/3
y = 1/3x -7/3
2007-04-26 15:46:59
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answer #5
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answered by Anonymous
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y+2=1/3(x-1)
so y=1/3x-7/3
2007-04-26 15:40:45
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answer #6
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answered by bruinfan 7
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Use the slope formula.
(y2 - y1)/(x2 - x1) = m
But we know m = 1/3,
(x1, y1) = (1, -2), and
(x2, y2) = (x, y).
(y - (-2)) / (x - 1) = 1/3
Put in slope-intercept form.
(y + 2) / (x - 1) = 1/3
y + 2 = (1/3)(x - 1)
y + 2 = (1/3)x - (1/3)
y = (1/3)x - (1/3) - 2
y = (1/3)x - (1/3) - (6/3)
y = (1/3)x - (7/3)
2007-04-26 15:41:32
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answer #7
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answered by Puggy 7
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y=mx+b
y=x/3+b
-2=1/3+b subtract 1/3 from each side
b=-7/3
y=x/3-7/3 or in standard form subtract x/3 from each side
-x/3+y=-7/3 multiply both sides by -3
x-3y=7
2007-04-26 15:45:20
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answer #8
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answered by yupchagee 7
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y--2=1/3(x-1)
y=1/3x-1.66666
2007-04-26 15:40:42
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answer #9
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answered by Anonymous
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