Solve the system 5x - y = 6 and 4x + 2y = 16?

Answer 1

5x - y = 6
4x + 2y = 16

I recommend the substitution method. Start by rewriting the first equation.

5x - y = 6
y = 5x - 6

Now use this value for y in the second equation.

4x + 2y = 16
4x + 2(5x - 6) = 16
4x + 10x - 12 = 16
14x = 28
x = 2

Now use this value for x in any of the other equations to solve for y.

y = 5x - 6 = 5(2) - 6 = 10 - 6 = 4

x = 2
y = 4

Answer 2

x=2 y=4

Answer 3

x= 2 y=4

Answer 4

a) 5x + 2y = 16. Find two numbers that add up to 16. One divisible by 5 and the other by 2 (10 and 6). Then divide 10 by 5 to give you x (2) and divide 6 by 2 to give y (3). x = 2, y = 3. b) 3x - 5 y = -9. Find two numbers where subtracting one from the other will give you -9. The first must be divisble by 3 and the second by 5. (6, 15) Then divide 6 by 3 to give you x and 15 by 5 to give you y. x = 2, y =3

Answer 5

x = 2, y =4

Answer 6

5x-y=6 *2
4x+2y=16 10x-2y=12 x=2 y=4

Answer 7

5x - y = 6
4x + 2y = 16 divide both sides by 2
2x+y=8
5x-y=6 add
7x=14 divide both sides by 7
x=2
5x-y=6 substitute 2 for x
5*2-y=6
10-y=6 subtract 10 from each side
-y=-4 divide both sides by -1
y=4
(2, 4) is the solution

check
4*2+2*4=16
8+8=16
16=16

Answer 8

Multiply the first equation by 2 and add it to the second to get: 14x=28, solve this to get x=2; substitute this back into the first equation to get 10-y=6, solve this oget y=4.

Answer 9

5x - y = 6
multiply both sides by 2
10x - 2y = 12 ------------(1)
4x + 2y = 16 -------------(2)

(1) + (2) =>
14x = 28 => x = 2

replace in (1): 20 - 2y = 12
8 = 2y
y = 4

Answer 10

5x - y = 6 ...............................*(1)
4x + 2y = 16?...................................(2)
2*(1) +(2) gives: :14x=28, So x=2. putting this in(1), we get
y=4