Well, there are 13,983,816 combinations, as said above, then:
1,2,3,4,5,6,7,8,9,12,23,34,45,56,67,78,89,123,234,345,456 etc,
so 9 between 1 and 10, 8 between 11 and 99, so:
Number of digits : number of ascending no's
1:9
2:8
3:7
4:6
5:5
6:4
7:3
So, thats 9+8+7+6+5+4+3 = 42, which takes you to 2,345,789, and there is 12,345,678 so I reckon 43. There you go, I might be wrong, but at least I tried.
Ashley
2007-04-26 08:10:23
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answer #3
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answered by Ashley 5
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49 x 48 x 47 x 46 x 45 x 44
Therefore, don't try to buy all the combinations for your National Lottery because you will lose money!!
HTH
2007-04-26 08:55:10
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answer #4
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answered by Anonymous
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44, if sequential, if not I can't be bothered to work it out, but I suspect about 7 million.
2007-04-26 08:02:10
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answer #5
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answered by Anonymous
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badly phrased question
could a combinations of 6 = 2,34,38,41,43,49.or 2,4,38,41,43,49
we have 11 or10 digits maybe???????????
2007-04-26 08:43:10
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answer #6
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answered by harry m 6
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